早教吧作业答案频道 -->数学-->
(1)(+12)-(-18)+(-7)-(+15)(2)-22×7-(-3)×6+5(3)(-1)2012×[(-2)5-32-514÷(-17)](4)-5m2n+4mn2-2mn+6m2n+3mn.
题目详情
(1)(+12)-(-18)+(-7)-(+15) (2)-2 2 ×7-(-3)×6+5 (3)(-1) 2012 ×[(-2) 5 -3 2 -
(4)-5m 2 n+4mn 2 -2mn+6m 2 n+3mn. |
(2)-2 2 ×7-(-3)×6+5
(3)(-1) 2012 ×[(-2) 5 -3 2 -
5 |
14 |
1 |
7 |
(4)-5m 2 n+4mn 2 -2mn+6m 2 n+3mn.
(2)-2 2 ×7-(-3)×6+5
(3)(-1) 2012 ×[(-2) 5 -3 2 -
5 |
14 |
1 |
7 |
(4)-5m 2 n+4mn 2 -2mn+6m 2 n+3mn.
(2)-2 2 ×7-(-3)×6+5
(3)(-1) 2012 ×[(-2) 5 -3 2 -
5 |
14 |
1 |
7 |
(4)-5m 2 n+4mn 2 -2mn+6m 2 n+3mn.
(2)-2 2 ×7-(-3)×6+5
(3)(-1) 2012 ×[(-2) 5 -3 2 -
5 |
14 |
1 |
7 |
(4)-5m 2 n+4mn 2 -2mn+6m 2 n+3mn.
2
2012 5 2
5 |
14 |
1 |
7 |
(4)-5m 2 n+4mn 2 -2mn+6m 2 n+3mn.
5 |
14 |
1 |
7 |
(4)-5m 2 n+4mn 2 -2mn+6m 2 n+3mn.
1 |
7 |
2 2 2
▼优质解答
答案和解析
(1)原式=12+18-7-15=30-22=8;
(2)原式=-4×7+18+5=-28+18+5=-5;
(3)原式=1×(-32-9+
×7)=-38.5;
(4)原式=m 2 n+4mn 2 +mn. (1)原式=12+18-7-15=30-22=8;
(2)原式=-4×7+18+5=-28+18+5=-5;
(3)原式=1×(-32-9+
×7)=-38.5;
(4)原式=m 2 n+4mn 2 +mn. (1)原式=12+18-7-15=30-22=8;
(2)原式=-4×7+18+5=-28+18+5=-5;
(3)原式=1×(-32-9+
×7)=-38.5;
(4)原式=m 2 n+4mn 2 +mn. (1)原式=12+18-7-15=30-22=8;
(2)原式=-4×7+18+5=-28+18+5=-5;
(3)原式=1×(-32-9+
×7)=-38.5;
(4)原式=m 2 n+4mn 2 +mn.
5 14 5 5 5 14 14 14 ×7)=-38.5;
(4)原式=m 2 2 n+4mn 2 2 +mn.
(1)原式=12+18-7-15=30-22=8; (2)原式=-4×7+18+5=-28+18+5=-5; (3)原式=1×(-32-9+
(4)原式=m 2 n+4mn 2 +mn. |
(2)原式=-4×7+18+5=-28+18+5=-5;
(3)原式=1×(-32-9+
5 |
14 |
(4)原式=m 2 n+4mn 2 +mn.
(2)原式=-4×7+18+5=-28+18+5=-5;
(3)原式=1×(-32-9+
5 |
14 |
(4)原式=m 2 n+4mn 2 +mn.
(2)原式=-4×7+18+5=-28+18+5=-5;
(3)原式=1×(-32-9+
5 |
14 |
(4)原式=m 2 n+4mn 2 +mn.
(2)原式=-4×7+18+5=-28+18+5=-5;
(3)原式=1×(-32-9+
5 |
14 |
(4)原式=m 2 n+4mn 2 +mn.
5 |
14 |
(4)原式=m 2 2 n+4mn 2 2 +mn.
看了 (1)(+12)-(-18)...的网友还看了以下:
(1)(+12)-(-18)+(-7)-(+15)(2)-22×7-(-3)×6+5(3)(-1) 2020-04-07 …
在方框内填运算符号,使等式成立.①2□2□2□2□2=0;②2□2□2□2□2=1;③2□2□2□ 2020-04-09 …
分式求和问题1/(2^k+1)+1/(2^k+2)+…+1/2^(k+1)为什么1/(2^k+1) 2020-04-26 …
阅读如下解题过程:(x^2+y^2)^-14(x^2+y^2)+13=0,请求x^2+y^2的值若 2020-04-27 …
四项因式分解的题.a^2-ab+ac-bc,x^2+ax^2+x+ax-1-a,ac^2+bd^2 2020-05-13 …
求高手帮看简单的lingo程序.data:xA=300;yA=300;enddatamin=((x 2020-05-13 …
3-2根号2=2-2根号2+1=根号2的平方-2根号2+1^2=(根号2-1)^2,4+2根号3= 2020-05-14 …
怎样使用matlab解下面的代数方程?急.syms a b c d e;2*b^2=a^2+c^2 2020-05-16 …
已知函数f(x)=sinx/2cosx/2+cos^2(x/2)-1/2f(x)=sin(x/2) 2020-05-16 …
合并同类项练习题(6m2n-5mn2)-6(m2n-mn2) 2020-08-01 …