早教吧 育儿知识 作业答案 考试题库 百科 知识分享

脱式计算,能简便的必须简便715×80%+715÷515÷(4-514-914)0.91×99+91×0.0120-6.25÷(1÷2)14+[78-(38-14)]1.125÷(25+2.5×80%)

题目详情
脱式计算,能简便的必须简便
7
15
×80%+
7
15
÷5         
1
5
÷(4-
5
14
-
9
14
)          
0.91×99+91×0.01
20-6.25÷(1÷2)
1
4
+[
7
8
-(
3
8
-
1
4
)]
1.125÷(
2
5
+2.5×80%)
脱式计算,能简便的必须简便
7
15
×80%+
7
15
÷5         
1
5
÷(4-
5
14
-
9
14
)          
0.91×99+91×0.01
20-6.25÷(1÷2)
1
4
+[
7
8
-(
3
8
-
1
4
)]
1.125÷(
2
5
+2.5×80%)

7
15
×80%+
7
15
÷5         
1
5
÷(4-
5
14
-
9
14
)          
0.91×99+91×0.01
20-6.25÷(1÷2)
1
4
+[
7
8
-(
3
8
-
1
4
)]
1.125÷(
2
5
+2.5×80%)
7
15
×80%+
7
15
÷5         
1
5
÷(4-
5
14
-
9
14
)          
0.91×99+91×0.0120-6.25÷(1÷2)
1
4
+[
7
8
-(
3
8
-
1
4
)]
1.125÷(
2
5
+2.5×80%)
7
15
×80%+
7
15
÷5         
1
5
÷(4-
5
14
-
9
14
)          
0.91×99+91×0.01
7
15
×80%+
7
15
÷5         
7
15
×80%+
7
15
÷5         
7
15
715771515
7
15
÷5         
7
15
715771515
1
5
÷(4-
5
14
-
9
14
)          
1
5
÷(4-
5
14
-
9
14
)          
1
5
151155
5
14
-
9
14
)          
5
14
514551414
9
14
)          
9
14
9149914140.91×99+91×0.0120-6.25÷(1÷2)
1
4
+[
7
8
-(
3
8
-
1
4
)]
1.125÷(
2
5
+2.5×80%)
20-6.25÷(1÷2)
1
4
+[
7
8
-(
3
8
-
1
4
)]
1
4
+[
7
8
-(
3
8
-
1
4
)]
1
4
141144
7
8
-(
3
8
-
1
4
)]
7
8
787788
3
8
-
1
4
)]
3
8
383388
1
4
)]
1
4
1411441.125÷(
2
5
+2.5×80%)
2
5
+2.5×80%)
2
5
252255
▼优质解答
答案和解析
(1)
7
15
×80%+
7
15
÷5
=
7
15
×0.8+
7
15
×0.2
=
7
15
×(0.8+0.2)
=
7
15
×1
=
7
15


(2)
1
5
÷(4-
5
14
-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
7
15
715777151515×80%+
7
15
÷5
=
7
15
×0.8+
7
15
×0.2
=
7
15
×(0.8+0.2)
=
7
15
×1
=
7
15


(2)
1
5
÷(4-
5
14
-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
7
15
715777151515÷5
=
7
15
×0.8+
7
15
×0.2
=
7
15
×(0.8+0.2)
=
7
15
×1
=
7
15


(2)
1
5
÷(4-
5
14
-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
7
15
715777151515×0.8+
7
15
×0.2
=
7
15
×(0.8+0.2)
=
7
15
×1
=
7
15


(2)
1
5
÷(4-
5
14
-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
7
15
715777151515×0.2
=
7
15
×(0.8+0.2)
=
7
15
×1
=
7
15


(2)
1
5
÷(4-
5
14
-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
7
15
715777151515×(0.8+0.2)
=
7
15
×1
=
7
15


(2)
1
5
÷(4-
5
14
-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
7
15
715777151515×1
=
7
15


(2)
1
5
÷(4-
5
14
-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
7
15
715777151515

(2)
1
5
÷(4-
5
14
-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
5
15111555÷(4-
5
14
-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
5
14
514555141414-
9
14

=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
9
14
914999141414)
=
1
5
÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
5
15111555÷[4-(
5
14
+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
5
14
514555141414+
9
14
)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
9
14
914999141414)]
=
1
5
÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
5
15111555÷[4-1]
=
1
5
÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
5
15111555÷3
=
1
15


(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
15
115111151515

(3)0.91×99+91×0.01
=0.91×99+0.91
=0.91×(99+1)
=0.91×100
=91

(4)20-6.25÷(1÷2)
=20-6.25÷0.5
=20-12.5
=7.5

(5)
1
4
+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
4
14111444+[
7
8
-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
7
8
78777888-(
3
8
-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
3
8
38333888-
1
4
)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
4
14111444)]
=
1
4
+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
4
14111444+[
7
8
-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
7
8
78777888-
1
8
]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
8
18111888]
=
1
4
+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
1
4
14111444+
3
4

=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
3
4
34333444
=1

(6)1.125÷(
2
5
+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875
2
5
25222555+2.5×80%)
=1.125÷(0.4+2)
=1.125÷2.4
=0.46875