早教吧作业答案频道 -->数学-->
数学直通车34+0.25=2×80%=180%-45=300×(1+20%)=10÷10%=7÷79=3÷4+14=27×2.8=107÷521=63×10%=
题目详情
数学直通车
| 2×80%= | 180%-
| ||||||||
300×(1+20%)= | 10÷10%= | 7÷
| ||||||||
3÷4+
|
|
| ||||||||
63×10%= |
3 |
4 |
4 |
5 |
3 |
4 |
3 |
4 |
3 |
4 |
4 |
5 |
4 |
5 |
4 |
5 |
7 |
9 |
7 |
9 |
7 |
9 |
7 |
9 |
1 |
4 |
2 |
7 |
10 |
7 |
5 |
21 |
1 |
4 |
1 |
4 |
1 |
4 |
2 |
7 |
2 |
7 |
2 |
7 |
10 |
7 |
5 |
21 |
10 |
7 |
5 |
21 |
10 |
7 |
5 |
21 |
5 |
21 |
▼优质解答
答案和解析
+0.25=1 2×80%=1.6 180%-
=1
+0.25=1
+0.25=1
3 3 34 4 4+0.25=1 2×80%=1.6 2×80%=1.6 180%-
=1 180%-
=1
4 4 45 5 5=1 300×(1+20%)=360 10÷10%=100 7÷
=9 300×(1+20%)=360 300×(1+20%)=360 10÷10%=100 10÷10%=100 7÷
=9 7÷
=9
7 7 79 9 9=9 3÷4+
=1
×2.8=0.8
÷
=6 3÷4+
=1 3÷4+
=1
1 1 14 4 4=1
×2.8=0.8
×2.8=0.8
2 2 27 7 7×2.8=0.8
÷
=6
÷
=6
10 10 107 7 7÷
=6
5 5 521 21 21=6
| 2×80%=1.6 | 180%-
| ||||||||
300×(1+20%)=360 | 10÷10%=100 | 7÷
| ||||||||
3÷4+
|
|
|
3 |
4 |
4 |
5 |
3 |
4 |
3 |
4 |
3 |
4 |
4 |
5 |
4 |
5 |
4 |
5 |
7 |
9 |
7 |
9 |
7 |
9 |
7 |
9 |
1 |
4 |
2 |
7 |
10 |
7 |
5 |
21 |
1 |
4 |
1 |
4 |
1 |
4 |
2 |
7 |
2 |
7 |
2 |
7 |
10 |
7 |
5 |
21 |
10 |
7 |
5 |
21 |
10 |
7 |
5 |
21 |
5 |
21 |
看了 数学直通车34+0.25=2...的网友还看了以下:
直接写出得数7÷1.4=0.23=0.77+0.33=1.65+1.5=25+13=25÷518= 2020-04-07 …
下图为我国某地区的等高线地形图,读图回答图中支流汇入干流处与甲处的纬度和经度差分别约为A.0.5° 2020-04-09 …
简算计算(5道,15.32*4+4.68/0.25 15/(0.15*0.4) 5.3+0.1+5 2020-05-16 …
看谁算行又对又快0.45÷0.05=4.3×0.5=1-0.08=600×0.01=0.65×1. 2020-05-17 …
matlab输出结果精度问题!急!clear; A=[4.7000000 24.5 24.1 10 2020-06-27 …
脱式计算.(能简算的要简算)(1)0.08×720×1.25(2)5.25×8.2+5.25×0. 2020-07-09 …
口算115-18+0.8=7.4-(114+25)=135-16-56=1.25×7×8=1237 2020-07-10 …
2.5+3.7=217÷7=70-34=1.2×0.5=1.3+27=1.5÷0.5=4.5-0. 2020-07-19 …
图中支流汇入干流处与甲点处的纬度和经度差分别约为()A.0.5°和1.5°B.0.25°和0.5°C 2020-11-17 …
数学,大家帮帮我5道递等式计算(能简则简)(1)23.56-23.56÷3.8×2.4(2)5.1× 2020-11-26 …