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sin4π/3cos5π/6tan(-4π/3)怎么做,求详细过程sin4π/3乘以cos5π/6乘以tan(-4π/3)=?
题目详情
sin4π/3cos5π/6tan(-4π/3)怎么做,求详细过程
sin4π/3乘以cos5π/6乘以tan(-4π/3)=?
sin4π/3乘以cos5π/6乘以tan(-4π/3)=?
▼优质解答
答案和解析
sin cos的周期为2π tan周期为π
sin4π=sin(4π-4π)=sin0=0
3cos5π=3cos(5π-4π)=3cosπ=3*(-1)=-3
6tan(-4π/3)=6tan(-4π/3+π)=6tan(-π/3)=-6tan(π/3)=-6√3
sin4π=sin(4π-4π)=sin0=0
3cos5π=3cos(5π-4π)=3cosπ=3*(-1)=-3
6tan(-4π/3)=6tan(-4π/3+π)=6tan(-π/3)=-6tan(π/3)=-6√3
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