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脱式计算．3.25÷2.5÷4537×0.5÷537×0.5（0.8+1125）×12.586.27-（28.9+16.27）257-27-571.6×[1÷（2.1-2.09）]．
题目详情
脱式计算．
3.25÷2.5÷4 5
×0.5÷5
×0.5 （0.8+
）×12.5 3.25÷2.5÷4 5
×0.5÷5
×0.5
×0.5÷5
×0.5
3 3 7 7
×0.5
3 3 7 7 （0.8+
）×12.5
）×12.5
1 1 125 125 86.27-（28.9+16.27） 2
-
-
1.6×[1÷（2.1-2.09）]． 86.27-（28.9+16.27） 2
-
-
-
-
5 5 7 7
-
2 2 7 7
5 5 7 7 1.6×[1÷（2.1-2.09）]．
| 3.25÷2.5÷4 | 5
| （0.8+
| ||||||
| 86.27-（28.9+16.27） | 2
| 1.6×[1÷（2.1-2.09）]． |
| 3.25÷2.5÷4 | 5
| （0.8+
| ||||||
| 86.27-（28.9+16.27） | 2
| 1.6×[1÷（2.1-2.09）]． |
| 3 |
| 7 |
| 3 |
| 7 |
| 1 |
| 125 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 3 |
| 7 |
| 1 |
| 125 |
| 1 |
| 125 |
| 1 |
| 125 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
| 5 |
| 7 |
▼优质解答
答案和解析
3.25÷2.5÷4
=3.25÷（2.5×4）
=3.25÷10
=0.325；
5
×0.5÷5
×0.5
=
×
÷
×
=
×
×
=
；
（0.8+
）×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
-
-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
3 3 37 7 7×0.5÷5
×0.5
=
×
÷
×
=
×
×
=
；
（0.8+
）×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
-
-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
3 3 37 7 7×0.5
=
×
÷
×
=
×
×
=
；
（0.8+
）×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
-
-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
38 38 387 7 7×
1 1 12 2 2÷
38 38 387 7 7×
1 1 12 2 2
=
×
×
=
；
（0.8+
）×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
-
-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
38 38 3814 14 14×
7 7 738 38 38×
1 1 12 2 2
=
；
（0.8+
）×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
-
-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
1 1 14 4 4；
（0.8+
）×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
-
-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
1 1 1125 125 125）×12.5
=0.8×12.5+
×12.5
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
-
-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
1 1 1125 125 125×12.5
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
-
-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
5 5 57 7 7-
-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
2 2 27 7 7-
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
5 5 57 7 7
=2
-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
5 5 57 7 7-（
+
）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
2 2 27 7 7+
5 5 57 7 7）
=2
−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160． 2
5 5 57 7 7−1
=
；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
5 5 57 7 7；
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
=3.25÷（2.5×4）
=3.25÷10
=0.325；
5
| 3 |
| 7 |
| 3 |
| 7 |
=
| 38 |
| 7 |
| 1 |
| 2 |
| 38 |
| 7 |
| 1 |
| 2 |
=
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
（0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 3 |
| 7 |
| 3 |
| 7 |
=
| 38 |
| 7 |
| 1 |
| 2 |
| 38 |
| 7 |
| 1 |
| 2 |
=
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
（0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 3 |
| 7 |
=
| 38 |
| 7 |
| 1 |
| 2 |
| 38 |
| 7 |
| 1 |
| 2 |
=
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
（0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 38 |
| 7 |
| 1 |
| 2 |
| 38 |
| 7 |
| 1 |
| 2 |
=
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
（0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 38 |
| 14 |
| 7 |
| 38 |
| 1 |
| 2 |
=
| 1 |
| 4 |
（0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 1 |
| 4 |
（0.8+
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 1 |
| 125 |
=0.8×12.5+
| 1 |
| 125 |
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 1 |
| 125 |
=10+0.1
=10.1；
86.27-（28.9+16.27）
=86.27-28.9-16.27
=（86.27-16.27）-28.9
=70-28.9
=41.1；
2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 5 |
| 7 |
=2
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 5 |
| 7 |
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 2 |
| 7 |
| 5 |
| 7 |
=2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160． 2
| 5 |
| 7 |
=
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
| 5 |
| 7 |
1.6×[1÷（2.1-2.09）]．
1.6×（1÷0.01）
=1.6×100
=160．
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