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(2012•安徽模拟)直接写出得数.1÷49=910-559+1=1-311+1011=(7÷17)×(17÷7)=10÷1%×11000=
题目详情
(2012•安徽模拟)直接写出得数.
1÷
=
910-559+1=
1-
+
=
(7÷
)×(
÷7)=
10÷1%×
=
=
910-559+1=
1-
+
=
(7÷
)×(
÷7)=
10÷1%×
=
4 4 9 9
+
=
(7÷
)×(
÷7)=
10÷1%×
=
3 3 11 11
=
(7÷
)×(
÷7)=
10÷1%×
=
10 10 11 11
)×(
÷7)=
10÷1%×
=
1 1 7 7
÷7)=
10÷1%×
=
1 1 7 7
=
1 1 1000 1000
1÷
4 |
9 |
910-559+1=
1-
3 |
11 |
10 |
11 |
(7÷
1 |
7 |
1 |
7 |
10÷1%×
1 |
1000 |
4 |
9 |
910-559+1=
1-
3 |
11 |
10 |
11 |
(7÷
1 |
7 |
1 |
7 |
10÷1%×
1 |
1000 |
4 |
9 |
3 |
11 |
10 |
11 |
(7÷
1 |
7 |
1 |
7 |
10÷1%×
1 |
1000 |
3 |
11 |
10 |
11 |
(7÷
1 |
7 |
1 |
7 |
10÷1%×
1 |
1000 |
10 |
11 |
1 |
7 |
1 |
7 |
10÷1%×
1 |
1000 |
1 |
7 |
1 |
7 |
10÷1%×
1 |
1000 |
1 |
7 |
1 |
1000 |
1 |
1000 |
▼优质解答
答案和解析
(1)1÷
=
;
(2)910-559+1=352;
(3)1-
+
=
;
(4)(7÷
)×(
÷7)=1;
(5)10÷1%×
=1.
4 4 49 9 9=
;
(2)910-559+1=352;
(3)1-
+
=
;
(4)(7÷
)×(
÷7)=1;
(5)10÷1%×
=1.
9 9 94 4 4;
(2)910-559+1=352;
(3)1-
+
=
;
(4)(7÷
)×(
÷7)=1;
(5)10÷1%×
=1.
3 3 311 11 11+
=
;
(4)(7÷
)×(
÷7)=1;
(5)10÷1%×
=1.
10 10 1011 11 11=
;
(4)(7÷
)×(
÷7)=1;
(5)10÷1%×
=1.
18 18 1811 11 11;
(4)(7÷
)×(
÷7)=1;
(5)10÷1%×
=1.
1 1 17 7 7)×(
÷7)=1;
(5)10÷1%×
=1.
1 1 17 7 7÷7)=1;
(5)10÷1%×
=1.
1 1 11000 1000 1000=1.
4 |
9 |
9 |
4 |
(2)910-559+1=352;
(3)1-
3 |
11 |
10 |
11 |
18 |
11 |
(4)(7÷
1 |
7 |
1 |
7 |
(5)10÷1%×
1 |
1000 |
4 |
9 |
9 |
4 |
(2)910-559+1=352;
(3)1-
3 |
11 |
10 |
11 |
18 |
11 |
(4)(7÷
1 |
7 |
1 |
7 |
(5)10÷1%×
1 |
1000 |
9 |
4 |
(2)910-559+1=352;
(3)1-
3 |
11 |
10 |
11 |
18 |
11 |
(4)(7÷
1 |
7 |
1 |
7 |
(5)10÷1%×
1 |
1000 |
3 |
11 |
10 |
11 |
18 |
11 |
(4)(7÷
1 |
7 |
1 |
7 |
(5)10÷1%×
1 |
1000 |
10 |
11 |
18 |
11 |
(4)(7÷
1 |
7 |
1 |
7 |
(5)10÷1%×
1 |
1000 |
18 |
11 |
(4)(7÷
1 |
7 |
1 |
7 |
(5)10÷1%×
1 |
1000 |
1 |
7 |
1 |
7 |
(5)10÷1%×
1 |
1000 |
1 |
7 |
(5)10÷1%×
1 |
1000 |
1 |
1000 |
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