因式分解题x²+x分之x²-1先因式分解在计算x²-8x+16分之x²+16,其中x=100x²-2x分之2y-xy,其中x-6,y=28

Question

因式分解题
x²+x分之x²-1 先因式分解在计算 x²-8x+16分之x²+16,其中x=100 x²-2x分之2y-xy,其中x-6,y=28

Answer 1

(x²-1) /(x²+x)
= (x+1)(x-1) / [x(x+1)]
= (x-1) /x
(x²-16) /(x²-8x+16)
= (x+4)(x-4) /(x-4)²
= (x+4)/(x-4)
= (100+4) /(100-4)
= 104 / 96
= 13 /12
(2y-xy) /(x²-2x)
= y(2-x) / [x(x-2)]
= -y(x-2) / [x(x-2)]
= -y/x
= -28/6
= - 14/3
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