y=sin(2x-π3)的单调递减区间是．

Question

y=sin(2x-(π)/(3))的单调递减区间是______．

Answer 1

由2kπ+(π)/(2)≤2x-(π)/(3)≤2kπ+(3π)/(2)，k∈z，可得 kπ+(5)/(12)π≤x ≤kπ+(11)/(12)π，k∈Z，
故函数y=sin(2x-(π)/(3))的单调递减区间是 [kπ+(5)/(12)π，kπ+(11)/(12)π]，k∈Z，
故答案为：[kπ+(5)/(12)π，kπ+(11)/(12)π]，k∈Z．