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计算(1+2i)^2+3(1-i)/2+i和1-根号3i/(根号3+i)^2
题目详情
计算(1+2i)^2+3(1-i)/2+i 和1-根号3i/(根号3+i)^2
▼优质解答
答案和解析
(1+2i)^2+3(1-i)/2+i
=1+4i-4+(1-i)(2-i)
=4i-3+1-3i
=i-2
(1-√3i)/(√3+i)²
=(1-√3i)/(2+2√3i)
=(1/2)*(1/4)*(1-√3i)²
=(1/8)*(-2-2√3i)
=-(1/4)-(√3/4)i
=1+4i-4+(1-i)(2-i)
=4i-3+1-3i
=i-2
(1-√3i)/(√3+i)²
=(1-√3i)/(2+2√3i)
=(1/2)*(1/4)*(1-√3i)²
=(1/8)*(-2-2√3i)
=-(1/4)-(√3/4)i
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