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求sec50°+tan10°的值.
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求sec50°+tan10°的值.
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答案和解析
sec50°+tan10°
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=2cos30°
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=
1 |
cos50° |
sin10° |
cos10° |
=
2sin50° |
2sin50°cos50° |
sin10° |
cos10° |
=
2sin50° |
sin100° |
sin10° |
cos10° |
=
2sin50° |
cos10° |
sin10° |
cos10° |
=
2sin50°+sin10° |
cos10° |
=
sin50°+(sin50°+sin10°) |
cos10° |
=
sin50°+cos20° |
cos10° |
=
cos40°+cos20° |
cos10° |
=
2cos30°cos10° |
cos10° |
=2cos30°
=
3 |
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