早教吧作业答案频道 -->数学-->
计算:sin65°+sin15°sin10°sin25°-cos15°cos80°的值为.
题目详情
计算:
|
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
▼优质解答
答案和解析
=
=
=
=
=cot15°
=tan75°=2+
故答案为:2+
=
=
=
=
=cot15°
=tan75°=2+
故答案为:2+
=
=
=
=
=cot15°
=tan75°=2+
故答案为:2+
=
=
=
=
=cot15°
=tan75°=2+
故答案为:2+
sin65°+sin15°sin10° sin25°-cos15°cos80° sin65°+sin15°sin10° sin65°+sin15°sin10° sin65°+sin15°sin10° sin25°-cos15°cos80° sin25°-cos15°cos80° sin25°-cos15°cos80°
=
=
=
=
=cot15°
=tan75°=2+
故答案为:2+
sin65°-
(cos25°-cos5° ) sin25°-
(cos95°+cos65° ) sin65°-
(cos25°-cos5° ) sin65°-
(cos25°-cos5° ) sin65°-
1 2 1 1 1 2 2 2 (cos25°-cos5° ) sin25°-
(cos95°+cos65° ) sin25°-
(cos95°+cos65° ) sin25°-
1 2 1 1 1 2 2 2 (cos95°+cos65° )
=
=
=
=cot15°
=tan75°=2+
故答案为:2+
sin65°+
cos5°
sin25°-
cos95°
sin65°+
cos5°
sin65°+
cos5°
1 2 1 1 1 2 2 2 sin65°+
1 2 1 1 1 2 2 2 cos5°
sin25°-
cos95°
sin25°-
cos95°
1 2 1 1 1 2 2 2 sin25°-
1 2 1 1 1 2 2 2 cos95°
=
=
=cot15°
=tan75°=2+
故答案为:2+
cos25°+cos5° cos65°-cos95° cos25°+cos5° cos25°+cos5° cos25°+cos5° cos65°-cos95° cos65°-cos95° cos65°-cos95°
=
=cot15°
=tan75°=2+
故答案为:2+
2cos15°cos10° 2sin80°sin15° 2cos15°cos10° 2cos15°cos10° 2cos15°cos10° 2sin80°sin15° 2sin80°sin15° 2sin80°sin15°
=cot15°
=tan75°=2+
故答案为:2+
3 3 3 3
故答案为:2+
3 3 3 3
=
=
=
=
=cot15° =tan75°=2+
故答案为:2+
|
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
=
sin65°-
| ||
sin25°-
|
=
| ||||
|
=
cos25°+cos5° |
cos65°-cos95° |
=
2cos15°cos10° |
2sin80°sin15° |
=cot15°
=tan75°=2+
3 |
故答案为:2+
3 |
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
=
sin65°-
| ||
sin25°-
|
=
| ||||
|
=
cos25°+cos5° |
cos65°-cos95° |
=
2cos15°cos10° |
2sin80°sin15° |
=cot15°
=tan75°=2+
3 |
故答案为:2+
3 |
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
=
sin65°-
| ||
sin25°-
|
=
| ||||
|
=
cos25°+cos5° |
cos65°-cos95° |
=
2cos15°cos10° |
2sin80°sin15° |
=cot15°
=tan75°=2+
3 |
故答案为:2+
3 |
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
=
sin65°-
| ||
sin25°-
|
=
| ||||
|
=
cos25°+cos5° |
cos65°-cos95° |
=
2cos15°cos10° |
2sin80°sin15° |
=cot15°
=tan75°=2+
3 |
故答案为:2+
3 |
sin65°+sin15°sin10° |
sin25°-cos15°cos80° |
=
sin65°-
| ||
sin25°-
|
=
| ||||
|
=
cos25°+cos5° |
cos65°-cos95° |
=
2cos15°cos10° |
2sin80°sin15° |
=cot15°
=tan75°=2+
3 |
故答案为:2+
3 |
sin65°-
| ||
sin25°-
|
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
=
| ||||
|
=
cos25°+cos5° |
cos65°-cos95° |
=
2cos15°cos10° |
2sin80°sin15° |
=cot15°
=tan75°=2+
3 |
故答案为:2+
3 |
| ||||
|
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
1 |
2 |
=
cos25°+cos5° |
cos65°-cos95° |
=
2cos15°cos10° |
2sin80°sin15° |
=cot15°
=tan75°=2+
3 |
故答案为:2+
3 |
cos25°+cos5° |
cos65°-cos95° |
=
2cos15°cos10° |
2sin80°sin15° |
=cot15°
=tan75°=2+
3 |
故答案为:2+
3 |
2cos15°cos10° |
2sin80°sin15° |
=cot15°
=tan75°=2+
3 |
故答案为:2+
3 |
3 |
故答案为:2+
3 |
3 |
看了 计算:sin65°+sin1...的网友还看了以下:
如图,四边形ABCD内接于⊙O,AB为⊙O的直径,C为BD弧的中点,AC、BD交于点E. (1)求 2020-05-13 …
连字成词(英语)l u o e b s r u s r e t o s w a e s r t e 2020-05-14 …
用所给字母拼成单词.1.a,l,a,d,s.2.a,d,o,s.3.c,o,r,p,n用所给字母拼 2020-05-15 …
u,i,n,c,o,s可以拼成什么单词?还有,o,s,l,h,u,d还有,t,p.s.n.e.r, 2020-05-23 …
AB是圆O的直径BC.CD分别是圆O的切线,切点分别为BD,E是BA和CD的延长线的交点1求ADo 2020-06-04 …
逻辑学的问题,关于直言命题的布尔解释的直言命题布尔解释道:I,O命题在S类为空时都为假,接着说,全 2020-06-08 …
A.根据释义,拼写单词.1.costingalotofmoneyx,p,s,i,e,e,e,n,v 2020-06-10 …
.已知:Kps(ZnS)=1.2×10-23,Ksp(MnS)=1.4×10-15则()A.ϕo( 2020-06-11 …
英语中S+V+P,S+V,S+V+O,S+V+O+O和S+V+O+C句型是指什么? 2020-06-12 …
英语高手给我想几个单词LOS分别以“L”“O”“S”“T”为开头的英文单词最好和“LOST”有点关 2020-06-12 …