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两个计算题!1.[(3x+1)^2][(3x-1)^2]2.(x+1)[(x^2)+1][(x^4)+1](x-1)
题目详情
两个计算题!
1.[(3x+1)^2][(3x-1)^2]
2.(x+1)[(x^2)+1][(x^4)+1](x-1)
1.[(3x+1)^2][(3x-1)^2]
2.(x+1)[(x^2)+1][(x^4)+1](x-1)
▼优质解答
答案和解析
1.[(3x+1)^2][(3x-1)^2]
=[(3x+1)(3x-1)]^2
=[9x^2-1]^2
=81x^4-18x^2+1
2.(x+1)[(x^2)+1][(x^4)+1](x-1)
=(x+1)(x-1)[(x^2)+1][(x^4)+1]
=(x^2-1)[(x^2)+1][(x^4)+1]
=[(x^4)-1][(x^4)+1]
=[(x^8)-1]
=[(3x+1)(3x-1)]^2
=[9x^2-1]^2
=81x^4-18x^2+1
2.(x+1)[(x^2)+1][(x^4)+1](x-1)
=(x+1)(x-1)[(x^2)+1][(x^4)+1]
=(x^2-1)[(x^2)+1][(x^4)+1]
=[(x^4)-1][(x^4)+1]
=[(x^8)-1]
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