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已知函数f(x)=sin(ωx+π/3),f(π/6)=f(π/4),且f(x)在区间(π/6,π/4)有最小值无最大值,则ω=
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已知函数f(x)=sin(ωx+π/3),f(π/6)=f(π/4),且f(x)在区间(π/6,π/4)有最小值无最大值,则ω=
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f(π/6)=sin(ωπ/6+π/3),f(π/4)=sin(ωπ/4+π/3),sin(ωπ/6+π/3)=sin(ωπ/4+π/3),ωπ/6+π/3=ωπ/4+π/3,ωπ/6+π/3=π-ωπ/4-π/3,解得:ω=0,ω=4/5,取ω=4/5,f(x)在区间(π/6,π/4)有最大值无最小值.
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