早教吧作业答案频道 -->数学-->
若(x^2+y^2)(x^2+y^2-2)+1=0,求x^2+y^2的植
题目详情
若(x^2+y^2)(x^2+y^2-2)+1=0,求x^2+y^2的植
▼优质解答
答案和解析
把x^2+y^2=t
(x^2+y^2)(x^2+y^2-2)+1=0
t(t-2)+1=0
t^2-2t+1=0
(t-1)^2=0
t=1=x^2+y^2
(x^2+y^2)(x^2+y^2-2)+1=0
t(t-2)+1=0
t^2-2t+1=0
(t-1)^2=0
t=1=x^2+y^2
看了 若(x^2+y^2)(x^2...的网友还看了以下：
这个符号“^”表方次数,.求下面3题的通解, y(x^2-xy+y^2)+x(x^2+xy+y^2 2020-05-14 …
已知函数f(x)对任意实数x,y均有f(x+y)+2=f(x)+f(y),且当x>0时,f(x)> 2020-06-12 …
谁帮我做因式分解1)5m2n-15mn22)-7x3y2-21x2y33)-15xy-5x24)5 2020-07-19 …
平方差公式已知x^2-y^2=24,x+y=4,求(x-y)^2的值1、已知x^2-y^2=24, 2020-08-03 …
1..设x/a+y/b+z/c=1,a/x+b/y+c/z=0,求x*2/a*2+y*2/b*2+z 2020-10-30 …
{x^2+y^2=12x+y=5{x^2-y^2+x-y-6=0x^2-y^2-x+y-4=0{x^ 2020-10-31 …
xyz=1,x+y+z=2,x^2+y^2+z^2=3,求x,y,z我解:xy=1/z,x+y=2- 2020-10-31 …
设x≥0,y≥0,x^2+(y^2/2)=11,设x≥0,y≥0,x^2+(y^2/2)=1,则x( 2020-10-31 …
设x≥0,y≥0,x^2+(y^2/2)=11,设x≥0,y≥0,x^2+(y^2/2)=1,则x( 2020-10-31 …
由(x^2+y^2+z^2)*(x+y+z)=x^3+y^3+z^3+(x+y)z^2+(y+z)x 2020-11-01 …