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(2012•长寿区)求未知数Χ0.5×(Χ-0.4)=5.8310+710Χ=311034:12=Χ:45Χ4=30%
题目详情
(2012•长寿区)求未知数Χ
0.5×(Χ-0.4)=5.8
+
Χ=3
:
=Χ:
=30%
0.5×(Χ-0.4)=5.8
3 |
10 |
7 |
10 |
1 |
10 |
3 |
4 |
1 |
2 |
4 |
5 |
Χ |
4 |
▼优质解答
答案和解析
(1)0.5×(X-0.4)=5.8,
0.5×X-0.5×0.4=5.8
0.5X-0.2=5.8,
0.5X-0.2+0.2=5.8+0.2,
0.5X=6,
0.5X÷0.5=6÷0.5,
X=12;
(2)
+
X=3
,
+
X-
=3
-
,
X=
,
X×
=
×
,
X=4;
(3)
:
=X:
,
X=
×
,
X×2=
×2,
X=1.2;
(4)
=30%,
=
,
10X=12,
10X÷10=12÷10,
X=1.2.
0.5×X-0.5×0.4=5.8
0.5X-0.2=5.8,
0.5X-0.2+0.2=5.8+0.2,
0.5X=6,
0.5X÷0.5=6÷0.5,
X=12;
(2)
3 |
10 |
7 |
10 |
1 |
10 |
3 |
10 |
7 |
10 |
3 |
10 |
1 |
10 |
3 |
10 |
7 |
10 |
14 |
5 |
7 |
10 |
10 |
7 |
14 |
5 |
10 |
7 |
X=4;
(3)
3 |
4 |
1 |
2 |
4 |
5 |
1 |
2 |
3 |
4 |
4 |
5 |
1 |
2 |
3 |
5 |
X=1.2;
(4)
X |
4 |
X |
4 |
3 |
10 |
10X=12,
10X÷10=12÷10,
X=1.2.
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