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递等式计算(1)(989+2119)÷37×12(2)2070÷[(1804-274)÷17](3)[293-(131+86)]×23(4)986÷34×45-1205.
题目详情
递等式计算
(1)(989+2119)÷37×12
(2)2070÷[(1804-274)÷17]
(3)[293-(131+86)]×23
(4)986÷34×45-1205.
(1)(989+2119)÷37×12
(2)2070÷[(1804-274)÷17]
(3)[293-(131+86)]×23
(4)986÷34×45-1205.
▼优质解答
答案和解析
(1)(989+2119)÷37×12,
=3108÷37×12,
=84×12,
=1008;
(2)2070÷[(1804-274)÷17],
=2070÷[1530÷17],
=2070÷90,
=23;
(3)[293-(131+86)]×23,
=[293-217]×23,
=76×23,
=1748;
(4)986÷34×45-1205,
=29×45-1205,
=1305-1205,
=100.
=3108÷37×12,
=84×12,
=1008;
(2)2070÷[(1804-274)÷17],
=2070÷[1530÷17],
=2070÷90,
=23;
(3)[293-(131+86)]×23,
=[293-217]×23,
=76×23,
=1748;
(4)986÷34×45-1205,
=29×45-1205,
=1305-1205,
=100.
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