早教吧作业答案频道 -->数学-->
sin47°-sin11°+sin61°-sin25°-cos7°的值是()
题目详情
sin47°-sin11°+sin61°-sin25°-cos7°的值是( )
▼优质解答
答案和解析
sin47°+sin61°-sin11°-sin25°
=(sin47°+sin61°)-(sin11°+sin25°)
=sin〔1/2*(47+61)+1/2*(47-61)〕+sin〔1/2*(47+61)-1/2*(47-61)〕-{sin〔1/2*(25+11)+1/2*(25-11)〕+sin〔1/2*(25+11)-1/2*(25-11)〕}
=sin(54+7)+sin(54-7)-〔sin(18+7)+sin(18-7)〕
=sin54cos7+cos54sin7+sin54cos7-cos54sin7-〔sin18cos7+cos18sin7+sin18cos7-cos18sin7〕
= 2sin54°*cos7°-2sin18°*cos7°
=2cos7°*(sin54°+sin(-18°))
=2cos7°*2sin18°*cos36°
=4 cos7°*sin18°*cos18°*cos36°/cos18°
=2cos7°*sin36°*cos36°/cos18°
=cos7°*sin72°/cos18°
=cos7°
所以sin47°-sin11°+sin61°-sin25°-cos7°=0
=(sin47°+sin61°)-(sin11°+sin25°)
=sin〔1/2*(47+61)+1/2*(47-61)〕+sin〔1/2*(47+61)-1/2*(47-61)〕-{sin〔1/2*(25+11)+1/2*(25-11)〕+sin〔1/2*(25+11)-1/2*(25-11)〕}
=sin(54+7)+sin(54-7)-〔sin(18+7)+sin(18-7)〕
=sin54cos7+cos54sin7+sin54cos7-cos54sin7-〔sin18cos7+cos18sin7+sin18cos7-cos18sin7〕
= 2sin54°*cos7°-2sin18°*cos7°
=2cos7°*(sin54°+sin(-18°))
=2cos7°*2sin18°*cos36°
=4 cos7°*sin18°*cos18°*cos36°/cos18°
=2cos7°*sin36°*cos36°/cos18°
=cos7°*sin72°/cos18°
=cos7°
所以sin47°-sin11°+sin61°-sin25°-cos7°=0
看了 sin47°-sin11°+...的网友还看了以下:
向量空间证明题怎么证明?设α1,α2...,αn和β1,β2,...βn是n维列向量空间R^n的两 2020-05-13 …
设f(x0在[a,b]单调连续,(a,b)可导,a=f(a)<f(b)=b求证:存在ξi∈(a,b 2020-05-14 …
数列问题若数列{an}是有穷等差数列,则与首末两项等距离的两项之和都相等,且等于首末两项之和,即a 2020-06-22 …
如果有穷数列a1,a2,a3.an(n为正整数)满足条件a1=an,a2=a(n-1).an=a1 2020-08-02 …
计算n+1阶行列式,每第i行的元素依次是ai^(n-k)*bi^k,(k=0,1,2,...,n) 2020-08-03 …
数列极限lim{((1³+2³+...n³)/n³)-4/n},n趋于无穷的极限?(1³+2³+.. 2020-11-01 …
lim(n趋近于无穷大)1/n∑(i=1到n)(1+i/n)∧(1/3)用定积分做.--!可不可以把 2020-11-11 …
设n=10,i=4,则执行赋值运算n%=i-1后,n的值是多少 2020-12-31 …
在计算机国考2级C语言中,填空的中括号与分号有没有空格的要求???sum=0;sum+=t[i][i 2021-01-01 …
关于螺旋填数,HELPME!源程序在这里,帮我看看啊:vara:array[1..10,1..10] 2021-01-13 …