⒈（1-π）º-√3·sin60°+（-2）³·（¼）²⒉√18-2/√2-√8/2+（√5-1）º⒊√8*sin45°+2-(√2-1)º⒋√12-4sin60°+(-1)³⒌1/2-tan60°+(√5-1)º+√3⒍2/(√3-1)-sin60º+(-2√5)º-√1

Question

⒈（1-π）º-√3·sin60°+（-2）³·（¼）²
⒉√18-2/√2-√8/2+（√5-1）º
⒊√8*sin45°+2-(√2-1)º
⒋√12-4sin60°+(-1)³
⒌1/2-tan60°+(√5-1)º+√3
⒍2/(√3-1)-sin60º+(-2√5)º-√12/4
⒎tan60º-2/(√3-1）+2+（x²+1）º
⒏3+（√3-π）º-2tan45°
⒐3+16/(-2)³+(2007-π/3)º-√3tan60°

Answer 1

⒈（1-π）º-√3·sin60°+（-2）³·（¼）²=1-3/2-8*1/8=-3/2
⒉√18-2/√2-√8/2+（√5-1）º=3√2-√2-√2+1=√2+1
⒊√8*sin45°+2-(√2-1)º=2+2-1=3
⒋√12-4sin60°+(-1)³=2√3-2√3=0
⒌1/2-tan60°+(√5-1)º+√3=1/2-√3+1=3/2-√3
⒍2/(√3-1)-sin60º+(-2√5)º-√12/4=√3+1-√3/2+1=2+√3/2
⒎tan60º-2/(√3-1）+2+（x²+1）º=√3-√3-1+2+1=2
⒏3+（√3-π）º-2tan45°3+1-2=2
⒐3+16/(-2)³+(2007-π/3)º-√3tan60°=3-2+1-3=-1 （多给点分吧）