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解不等式组2x+14<5(x+4)x≤2x3+1.

题目详情
2x+14<5(x+4)
x≤
2x
3
+1
2x+14<5(x+4)
x≤
2x
3
+1
2x+14<5(x+4)
x≤
2x
3
+1
2x+14<5(x+4)
x≤
2x
3
+1
2x+14<5(x+4)
x≤
2x
3
+1
2x+14<5(x+4)2x+14<5(x+4)x≤
2x
3
+1x≤
2x
3
+1
2x
3
2x2x33
▼优质解答
答案和解析
2x+14<5(x+4)①
x≤
2x
3
+1②

∵由①得:x>-2,
由②得:x≤3,
∴原不等式组的解集为-2<x≤3.
2x+14<5(x+4)①
x≤
2x
3
+1②
2x+14<5(x+4)①
x≤
2x
3
+1②
2x+14<5(x+4)①
x≤
2x
3
+1②
2x+14<5(x+4)①
x≤
2x
3
+1②
2x+14<5(x+4)①2x+14<5(x+4)①2x+14<5(x+4)①x≤
2x
3
+1②x≤
2x
3
+1②x≤
2x
3
2x2x2x333+1②
∵由①得:x>-2,
由②得:x≤3,
∴原不等式组的解集为-2<x≤3.