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2.设f(x)=cosx,f(φ(x))=1−x2,则φ(x)的定义域是().(−∞,+∞)[−2√,2√][−1,1][0,π是·1-x^2
题目详情
2.设f(x)=cosx,f(φ(x))=1−x2,则φ(x)的定义域是( ).
(−∞,+∞)
[−2√,2√]
[−1,1]
[0,π
是·1-x^2
(−∞,+∞)
[−2√,2√]
[−1,1]
[0,π
是·1-x^2
▼优质解答
答案和解析
∵f(x)=cosx,f(φ(x))=1−x2,
∴φ(x)=COS^(-1)(1-X²)
∴1-X²∈[-1,1]
∴[−2√,2√]
∴φ(x)=COS^(-1)(1-X²)
∴1-X²∈[-1,1]
∴[−2√,2√]
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