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（x²+2xy+y²/x²y+xy²）-（x²-2xy+y²/x²y-xy²）
题目详情
（x²+2xy+y²/x²y+xy²）-（x²-2xy+y²/x²y-xy²）
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答案和解析
(x^2+2xy+y^2)/(x^2y+xy^2)-(x^2-2xy+y^2)/(x^2y-xy^2)
=(x+y)^2/[xy(x+y)]-(x-y)^2/[xy(x-y)]
=(x+y)/xy-(x-y)/xy
=(x+y-x+y)/xy
=2y/xy
=2/x
=(x+y)^2/[xy(x+y)]-(x-y)^2/[xy(x-y)]
=(x+y)/xy-(x-y)/xy
=(x+y-x+y)/xy
=2y/xy
=2/x
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