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sin^220+cos^250+sin20cos50
题目详情
sin^220 +cos^250+ sin20cos50
▼优质解答
答案和解析
(sin20)^2+(cos50)^2+sin20cos50
=(sin20)^2+(sin40)^2+sin20sin40
=(sin20+sin40)^2-sin20sin40
=[sin(30-10)+sin(30+10)]^2-sin(30-10)sin(30+10)
=(2sin30cos10)^2-[(sin30cos10)^2-(cos30sin10 )^2]
=(cos10)^2-1/4(cos10)^2+3/4(sin10 )^2
=3/4(cos10)^2+3/4(sin10 )^2
=3/4[(cos10)^2+(sin10 )^2]
=3/4
=(sin20)^2+(sin40)^2+sin20sin40
=(sin20+sin40)^2-sin20sin40
=[sin(30-10)+sin(30+10)]^2-sin(30-10)sin(30+10)
=(2sin30cos10)^2-[(sin30cos10)^2-(cos30sin10 )^2]
=(cos10)^2-1/4(cos10)^2+3/4(sin10 )^2
=3/4(cos10)^2+3/4(sin10 )^2
=3/4[(cos10)^2+(sin10 )^2]
=3/4
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