如下：2x0000;x11000;00002x;0001x1;001x10;10(1+x)100.帮我化简成带x的式子就行,

Question

如下：
2 x 0 0 0 0 ;
x 1 1 0 0 0;
0 0 0 0 2 x;
0 0 0 1 x 1;
0 0 1 x 1 0;
1 0 (1+x) 1 0 0.
帮我化简成带x的式子就行,

Answer 1

r1-xr2
2-x^2 0 -x 0 0 0
x 1 1 0 0 0
0 0 0 0 2 x
0 0 0 1 x 1
0 0 1 x 1 0
1 0 1+x 1 0 0
按第2列展开,D=1*(-1)^(2+2)*
2-x^2 -x 0 0 0
0 0 0 2 x
0 0 1 x 1
0 1 x 1 0
1 1+x 1 0 0
r1-(2-x^2)r5
0 x^3+x^2-3x-2 x^2-2 0 0
0 0 0 2 x
0 0 1 x 1
0 1 x 1 0
1 1+x 1 0 0
按第1列展开,D=1*(-1)^(5+1)*
x^3+x^2-3x-2 x^2-2 0 0
0 0 2 x
0 1 x 1
1 x 1 0
r1-(x^3+x^2-3x-2)r4
0 -x^4-x^3+4x^2+2x-2 -x^3-x^2+3x+2 0
0 0 2 x
0 1 x 1
1 x 1 0
按第1列展开,D=1*(-1)^(4+1)*
-x^4-x^3+4x^2+2x-2 -x^3-x^2+3x+2 0
0 2 x
1 x 1
同样,r1+(x^4+x^3-4x^2-2x+2)r3
0 x^5+x^4-5x^3-3x^2+5x+2 x^4+x^3-4x^2-2x+2
0 2 x
1 x 1
按第1列展开,D=-1*1*(-1)^(3+1)*
x^5+x^4-5x^3-3x^2+5x+2 x^4+x^3-4x^2-2x+2
2 x
D = (-1)* [(x^5+x^4-5x^3-3x^2+5x+2)x-2(x^4+x^3-4x^2-2x+2)]
= - x^6 - x^5 + 7x^4 + 5x^3 - 13x^2 - 6x + 4