用递等式计算．5304-5304÷221+22019.5×0.2-2.07÷23（89+123−127）×634.8×512+7.2÷225334+334×225−225÷115[2-（123−1.5）÷1512]×638

Question

用递等式计算． 5304-5304÷221+220	19.5×0.2-2.07÷23	（(8)/(9)+1(2)/(3)−1(2)/(7)）×63
4.8×(5)/(12)+7.2÷2(2)/(5)	3(3)/(4)+3(3)/(4)×2(2)/(5)−2(2)/(5)÷1(1)/(5)	[2-（1(2)/(3)−1.5）÷1(5)/(12)]×6(3)/(8)

Answer 1

（1）5304-5304÷221+220
=5304-24+220
=5280+220
=5500；

（2）19.5×0.2-2.07÷23
=3.9-0.09
=3.81；

（3）（(8)/(9)+1(2)/(3)−1(2)/(7)）×63
=(8)/(9)×63+1(2)/(3)×63-1(2)/(7)×63
=56+105-81
=161-81
=80；

（4）4.8×(5)/(12)+7.2÷2(2)/(5)
=4.8×(5)/(12)+7.2×(5)/(12)
=（4.8+7.2）×(5)/(12)
=12×(5)/(12)
=5；

（5）3(3)/(4)+3(3)/(4)×2(2)/(5)−2(2)/(5)÷1(1)/(5)
=3(3)/(4)×（1+2(2)/(5)）-2(2)/(5)×(5)/(6)
=3(3)/(4)×3(2)/(5)-2(2)/(5)×(5)/(6)
=12(3)/(4)-2
=10(3)/(4)；

（6）[2-（1(2)/(3)−1.5）÷1(5)/(12)]×6(3)/(8)
=[2-(1)/(6)÷1(5)/(12)]×

作业帮用户 2017-09-18