Johnsonisa(n)customerofthisshopandhecomesheretwiceaweek.A.commonB.regularC.normalD.ordinary
Johnson is a (n) ______customer of this shop and he comes here twice a week.
A. common B. regular C. normal D. ordinary
B
已知数列a(n)为等比数列,a(4)=16,q=2,数列b(n)前N项和s(n)=1/2*n的平方 2020-05-13 …
关于极限的题目a(n)=n*sin(∏/n)(n>=1)当n→∞时,求a(n)(n)为下标a(n) 2020-05-14 …
数列a[n+1]=k+(2k+1)a[n]+(k(k+1)a[n](a[n+1]))^1/2 已知 2020-05-16 …
数列a[n+1]=k+(2k+1)a[n]+(k(k+1)a[n]a[n+1])^1/2 已知a1 2020-05-16 …
求证:(1)A(n+1,n+1)-A(n,n)=n^2A(n-1,n-1);(2)C(m,n+1) 2020-06-03 …
1.已知数列{a(n)}满足a(n)a(n+1)a(n+2)a(n+3)=24,且a1=1a2=2 2020-07-09 …
立方差公式的推广证明过程(1)a^n-b^n=(a-b)[a^(n-1)+a^(n-2)*b+.. 2020-07-11 …
用a^n-b^n=(a-b)(a^(n-1)+a^(n-2)*b+...+ab^(n-2)+b^( 2020-07-14 …
什么是二项式的通式?在二项式定理(a+b)^n=C(n,0)a^n+C(n,1)a^(n-1)b+ 2020-07-31 …
分解因式谁能给我讲解下!a^n+b^n=(a+b)([a^{n-1}]-[a^{n-2}]*b+[a 2020-11-20 …