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下列整式是否作因式分解?如果能,请完成因式分解1.(1-x²)(1-y²)-4xy2.(2x²-3x+1)²-22x²+33x-1大侠们救救我呗(1-x²)(1-y²)-4xy和.(2x²-3x+1)²-22x²+33x-1HELP
题目详情
下列整式是否作因式分解?如果能,请完成因式分解
1.(1-x²)(1-y²)-4xy 2.(2x²-3x+1)²-22x²+33x-1 大侠们 救救我呗
(1-x²)(1-y²)-4xy 和.(2x²-3x+1)²-22x²+33x-1 HELP
1.(1-x²)(1-y²)-4xy 2.(2x²-3x+1)²-22x²+33x-1 大侠们 救救我呗
(1-x²)(1-y²)-4xy 和.(2x²-3x+1)²-22x²+33x-1 HELP
▼优质解答
答案和解析
1.
(1-x²)(1-y²)-4xy
=1-x²-y²+x²y²-4xy
=x²y²-2xy+1-(x²+2xy+y²)
=(xy-1)²-(x+y)²
=[(xy-1)+(x+y)][(xy-1)-(x+y)]
=(x+y+xy-1)(xy-x-y-1)
2.
(2x²-3x+1)²-22x²+33x-1
=(2x²-3x+1)²-1-11x(2x-3)
=(2x²-3x+1+1)(2x²-3x+1-1)-11x(2x-3)
=(2x²-3x+2)(2x²-3x)-11x(2x-3)
=x(2x²-3x+2)(2x-3)-11x(2x-3)
=x(2x-3)[(2x²-3x+2)-11]
=x(2x-3)(2x²-3x-9)
=x(2x-3)(x-3)(2x+3)
如果不懂,祝学习愉快!
(1-x²)(1-y²)-4xy
=1-x²-y²+x²y²-4xy
=x²y²-2xy+1-(x²+2xy+y²)
=(xy-1)²-(x+y)²
=[(xy-1)+(x+y)][(xy-1)-(x+y)]
=(x+y+xy-1)(xy-x-y-1)
2.
(2x²-3x+1)²-22x²+33x-1
=(2x²-3x+1)²-1-11x(2x-3)
=(2x²-3x+1+1)(2x²-3x+1-1)-11x(2x-3)
=(2x²-3x+2)(2x²-3x)-11x(2x-3)
=x(2x²-3x+2)(2x-3)-11x(2x-3)
=x(2x-3)[(2x²-3x+2)-11]
=x(2x-3)(2x²-3x-9)
=x(2x-3)(x-3)(2x+3)
如果不懂,祝学习愉快!
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