求个反函数求函数y=1+2sin((x-1)/(x+1))的反函数!要有具体过程,

Question

求个反函数
求函数y=1+2sin((x-1)/(x+1))的反函数!要有具体过程,

Answer 1

2sin(x-1/1+x)=y-1
x-1/1+x=arcsin[(y-1)/2]
x-1=arcsin[(y-1)/2]+x*arcsin[(y-1)/2]
{1-arcsin[(y-1)/2]}x=1+arcsin[(y-1)/2]
x={1+arcsin[(y-1)/2]}/{1-arcsin[(y-1)/2]}
其中-1