复数z1，z2在复平面内对应的点关于直线y=x对称，且z1=3+2i，则z1z2=（）A.1213+513iB.-1213+513iC.-1213-513iD.1213-513i

Question

复数z₁，z₂在复平面内对应的点关于直线y=x对称，且z₁=3+2i，则

(z1)/(z2)=（　　）

A.

(12)/(13)+(5)/(13)i

B. -

(12)/(13)+(5)/(13)i

C. -

(12)/(13)-(5)/(13)i

D.

(12)/(13)-(5)/(13)i

Answer 1

复数z₁，z₂在复平面内对应的点关于直线y=x对称，且z₁=3+2i，∴z₂=2+3i．
则(z1)/(z2)=(3+2i)/(2+3i)=((3+2i)(2-3i))/((2+3i)(2-3i))=(12-5i)/(13)=(12)/(13)-(5)/(13)i．
故选：D．