已知u=x^2+y^2,v=x+y求δx/δu与δu/δx之值(偏微分),

Question

已知u=x^2+y^2,v=x+y 求δx/δu与δu/δx之值(偏微分),

Answer 1

δu/δx=2x;
x=(u-y^2)^(-1/2)
则δx/δu=-1/2(u-y^2)^(-3/2)