已知复数z满足（3+i）z=10i（i为虚数单位），则z的模为．

Question

已知复数z满足（3+i）z=10i（i为虚数单位），则z的模为______．

Answer 1

z= (10i)/(3+i) = (10i(3-i))/((3+i)(3-i)) = (10+30i)/(10) =1+3i
∴|z|=

1 2 +3 2

=

10

故答案为：

10