早教吧作业答案频道 -->英语-->
Unfortunatelyforhim,Socratesquestionedtoomuch.Healwaysaskedchallengingquestionstoeveryonehemet,(66)manypeopleinAthens.Finally,somepeoplehad(67)ofhim,sotheytookhimto(68)forquestioningthee
题目详情
Unfortunately for him,Socrates questioned too much.He always asked challenging questions to everyone he met,(66)___ many people in Athens.Finally,some people had (67)___ of him,so they took him to (68)___ for questioning the existence of the Greek gods and for (69)___ the young people of Athens.At his (70)___,he defended himself by asking his judges yet more questions.
▼优质解答
答案和解析
(66)upsetting.考查非谓语动词.根据He always asked challenging questions to everyone he met可知他这种做法让许多人不自在,所以用 upsetting 做结果状语.
(67)enough.考查固定短语.根据上文可知"他总是问别人问题,让别人不自在",所以本句表示"人们厌烦了他",have enough of sth表示"(对某人或某事) 感到厌烦;"
(68)court.考查名词. questioning the existence of the Greek gods 表示"质疑上帝的存在",所以前句表示"把他带到法庭"
(69)corrupting.考查非谓语动词.和questioning the existence of the Greek gods 并列用corrupting,表示"误导雅典的年轻人".
(70)trial.考查名词.根据68题可知本句表示"在他受审的时候".
(67)enough.考查固定短语.根据上文可知"他总是问别人问题,让别人不自在",所以本句表示"人们厌烦了他",have enough of sth表示"(对某人或某事) 感到厌烦;"
(68)court.考查名词. questioning the existence of the Greek gods 表示"质疑上帝的存在",所以前句表示"把他带到法庭"
(69)corrupting.考查非谓语动词.和questioning the existence of the Greek gods 并列用corrupting,表示"误导雅典的年轻人".
(70)trial.考查名词.根据68题可知本句表示"在他受审的时候".
看了Unfortunatelyfo...的网友还看了以下:
求纠错!输入整数 m 和正整数 n ,按下列公式计算 s输入整数 m 和正整数 n ,按下列公式计 2020-05-17 …
1.已知数列{a(n)}满足a(n)a(n+1)a(n+2)a(n+3)=24,且a1=1a2=2 2020-07-09 …
下列词语中加点字的字音全都正确的一组是()A.愤懑(mèn)越俎(zǔ)代庖恫吓(xià)弱不禁( 2020-07-12 …
给出下列命题(1)实数的共轭复数一定是实数;(2)满足|z-i|+|z+i|=2的复数z点的轨迹是 2020-07-30 …
已知一个边长为a的等边三角形,现将其边长n(n为大于2的整数)等分,并以相邻等分点为顶点向外作小等 2020-08-01 …
①用初等行变换将矩阵化为约化阶梯型[1-13-1]2-1-143-22310-45②设ai(i=1 2020-08-02 …
求证e^i(4π/n)+e^i(8π/n)+...+e^i4(n-1)π/n+e^i(4nπ/n)= 2020-11-01 …
设f(i,k)=i•2(k-1)(i∈N*,k∈N*),如f(2,3)=2×2(3-1)=8.对于正 2020-11-01 …
下列各项中读音错误的一项是:()A.闷热mēn愤懑mèn分娩miǎn酩酊dǐngB.荒谬mìù脉脉m 2020-11-04 …
在资金时间价值计算时,i和n给定,下列等式中正确的有().A.(F/A,i,n)=[(P/F,i,n 2021-01-14 …