help因式分解(x²+5x+3)(x²+5x-2)-6(x-1)(x+2)(x-3)(x+4)+24

Question

help 因式分解
(x²+5x+3)(x²+5x-2)-6
(x-1)(x+2)(x-3)(x+4)+24

Answer 1

(x²+5x+3)(x²+5x-2)-6
=(x²+5x)²+3(x²+5x)-2(x²+5x)-12
=(x²+5x)²+(x²+5x)-12
=(x²+5x+4)(x²+5x-3)
=(x+1)(x+4)(x²+5x-3)
(x-1)(x+2)(x-3)(x+4)+24
=(x²+x-2)(x²+x-12)+24
=(x²+x)²-12(x²+x)-2(x²+x)+24+24
=(x²+x)²-14(x²+x)+48
=(x²+x-6)(x²+x-8)
=(x+3)(x-2)(x²+x-8)
不懂追问~