四道一元一次方程的解法1.>1/3x-1=1/2x+22.>1-x-3/3=x+23.>x+2/4-1-2x/12=14.>x-3(5x-1/6-4x+1/3)=2(x+2)有些不清楚的空格的2.>1-(x-3)/3=x+23.>（x+2）/4-（1-2x）/12=1

Question

四道一元一次方程的解法
1.> 1/3x -1 = 1/2x +2
2.> 1- x-3/3 = x+2
3.> x+2/4 - 1-2x/12=1
4.> x-3(5x-1/6 - 4x+1/3)=2(x+2)
有些不清楚的空格的
2.> 1- (x-3)/3 = x+2
3.> （x+2）/4 -（ 1-2x）/12=1

Answer 1

1.> 1/3x -1 = 1/2x +2
2x-6=3x+2
3x-2x=-6-2
x=-8
2.> 1- x-3/3 = x+2
3-(x-3)=3(x+2)
6-x=3x+6
4x=0
x=0
3.> x+2/4 - 1-2x/12=1
3(x+2)-(1-2x)=12
3x+6-x+2x=12
4x=6
x=3/2
4.> x-3(5x-1/6 - 4x+1/3)=2(x+2)
2x-[5x-1-2(4x+1)]=4(x+2)
2x+3x+3=4x+8
5x-4x=8-3
x=5