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x十y十Z=一1,4x一2y十3z=5,y一z=8一2x,
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x十y十Z=一1,4x一2y十3z=5,y一z=8一2x,
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答案和解析
x十y十Z=一1 (1)
4x一2y十3z=5 (2)
y一z=8一2x (3)
(1)乘2得:
2x+2y+2z=-2,再加(2)式得:
6x+5z=3 (4)
(3)乘2得:
2y-2z=16-4x,再加(2)式得:
4x+z=21-4x
8x+z=21(5)
(5)乘以5得:
40x+5z=105 减去(4)式得:
34x=102
x=3;
代入(5)得:
24+z=21
z=-3;
所以y=-1-x-z=-1-3+3=-1;
解集为:
x=3;
y=-1;
z=-3;
4x一2y十3z=5 (2)
y一z=8一2x (3)
(1)乘2得:
2x+2y+2z=-2,再加(2)式得:
6x+5z=3 (4)
(3)乘2得:
2y-2z=16-4x,再加(2)式得:
4x+z=21-4x
8x+z=21(5)
(5)乘以5得:
40x+5z=105 减去(4)式得:
34x=102
x=3;
代入(5)得:
24+z=21
z=-3;
所以y=-1-x-z=-1-3+3=-1;
解集为:
x=3;
y=-1;
z=-3;
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