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若x^2+y^2-2x+6y+10=0,则(x+y)^5=?
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若x^2+y^2-2x+6y+10=0,则(x+y)^5=?
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答案和解析
x^2+y^2-2x+6y+10=0
(x-1)^2+(y+3)^2=0
x-1=0,y+3=0
x=1,y=-3
(x+y)^5=(1-3)^5=-32
(x-1)^2+(y+3)^2=0
x-1=0,y+3=0
x=1,y=-3
(x+y)^5=(1-3)^5=-32
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