早教吧作业答案频道 -->英语-->
Tohiscredit,histranslationmanagestobetothespiritoftheoriginal.A.faithfulB.admirableC.automaticD.considerate
题目详情
To his credit, his translation manages to be ________ to the spirit of the original.
|
▼优质解答
答案和解析
A |
|
看了Tohiscredit,his...的网友还看了以下:
若f(x)与g(x)在(-∞,+∞)上皆可导,且f(x)<g(x),则必有()A.f(-x)>g( 2020-06-12 …
若函数f(x)与g(x)在(-∞,+∞)内可导,且f(x)<g(x),则必有()A.f(-x)>g 2020-06-12 …
设f(x)为连续函数,f(0)=a,F(t)=∫∫∫Ω{z-f(x^2+y^2+z^2)]dv,其 2020-06-15 …
设函数f(x)连续,且f(0)≠0,求极限limx→0∫x0(x?t)f(t)dtx∫x0f(x? 2020-07-09 …
针对程序段:IF(A||B||C)THENW=W/X,对于(A,B,C)的取值,(57)测试用例能 2020-07-10 …
变限积分[a,b]上的积分∫[f(x+h)-f(x)]dx令x+h=t,那原式=∫[a+h,b+h 2020-07-11 …
下列各项中字音不正确的一项是:()A.涕(tì)泪梯(tī)子府第(dì)B.饿莩(fú)俘(fú 2020-07-12 …
F(根号X+1)=x+2根号x求fx设√x+1=tx=(t-1)²f(√x+1)=f(t)=(t- 2020-07-18 …
求助微积分强人帮忙解这个二阶方程f"(t)=a1=(π〖d/2〗^2P(t)-k[x+f(t)]- 2020-07-31 …
变上限积分求导f(x)=∫(0,x)(x-t)^2*f(t)dt如何对x求导?原题:函数f(x)满 2020-07-31 …