已知复数Z1=2-i，Z2=1-3i，则复数iz1+z25=−15i−15i．

Question

已知复数Z₁=2-i，Z₂=1-3i，则复数(i)/(z1)+(z2)/(5)=

−(1)/(5)i

−(1)/(5)i

．

Answer 1

∵复数Z₁=2-i，Z₂=1-3i，∴(i)/(z1)+(z2)/(5)=(i)/(2−i)+(1−3i)/(5) 
=(i(2+i))/((2−i)(2+i))+(1−3i)/(5)=(−1+2i+1−3i)/(5)=−(1)/(5)i，
故答案为 −(1)/(5)i．