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如图,以原点O为圆心,OB为半径画弧与数轴交于点A,且点A表示的数为x,则x2﹣10的立方根为()

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如图,以原点O为圆心,OB为半径画弧与数轴交于点A,且点A表示的数为x,则x2﹣10的立方根为(  )                                               

                                                            

A                B.﹣             C.2                            D.﹣2

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答案和解析

D【分析】根据勾股定理列式求出x2,再利用立方根的定义解答.                 

【解答】由图可知,x2=12+12=2,                                                     

则x2﹣10=2﹣10=﹣8,                                                                           

﹣8的立方根为﹣2,                                                                         

故选:D.                                                                                         

【点评】本题考查了实数与数轴,主要是数轴上无理数的作法,需熟练掌握.