高中数学问题、一个题五分、在线等、都是基础、求速度、【三角函数的】sin(2kπ+α)=cos(2kπ+α)=sin(π+α)=sin(π-α)=cos(π+α)=cos(π-α)=cos(½π+α)=sin(½π+α)=cos(½π-α)=sin(½π-α)=sin（α+β

Question

高中数学问题、一个题五分、在线等、都是基础、求速度、【三角函数的】
sin(2kπ+α)=
cos(2kπ+α)=
sin(π+α)=
sin(π-α)=
cos(π+α)=
cos(π-α)=
cos(½π+α)=
sin(½π+α)=
cos(½π-α)=
sin(½π-α)=
sin（α+β）=
sin2α=
cos2α=
全答出来了、把剩下的分补上、求速度、

Answer 1

sin(2kπ+α)=sina
cos(2kπ+α)=cosa
sin(π+α)=-sina
sin(π-α)=sina
cos(π+α)=-cosa
cos(π-α)=-cosa
cos(½π+α)=-sina
sin(½π+α)=cosa
cos(½π-α)=sina
sin(½π-α)=cosa
sin（α+β）=sinαcosβ+cosαsinβ
sin2α=2sinacosa
cos2α=cosa^2-sina^2