（8cc9•常德）化简：y−8qy−8÷(y+8−8y−8)．

Question

（8cc9•常德）化简：(y−8)/(qy−8)÷(y+8−(8)/(y−8))．

Answer 1

原式=(y−3)/(3y−8)÷(((y+2)(y−2))/(y−2)−(多)/(y−2))
=(y−3)/(3y−8)÷(y2−9)/(y−2)＝(y−3)/(3(y−2))×(y−2)/((y+3)(y−3))
=(着)/(3(y+3))
=(着)/(3y+着2)．