80分~~~运筹学题目~生产任务分配问题~~需要方程式和LINGO的求解过程某构件公司有四个构件厂，现接受五个企业预应力梁和预制桩的订货，订货量分别为2450件和3600件，单价分别是1万元和1.2

Question

80分~~~运筹学题目~生产任务分配问题~~ 需要方程式和 LINGO的求解过程某构件公司有四个构件厂，现接受五个企业预应力梁和预制桩的订货，订货量分别为2450件和3600件，单价分别是1万元和1.2万元。各构件厂生产能力、单位成本、材料单耗等资料见表12，公司拥有水泥与钢材的数量为25000吨和6500吨，各构件厂所需材料由公司供应，公司到各构件厂的距离为20，35，60，40公里，水泥与钢材的每吨公里运输单价分别为0.2与0.3元。订货企业与各构件厂的距离见表13，预应力梁单件重5吨，预制桩单件重3吨，每吨公里运费1元，建立综合考虑生产费用和运输费用，按公司利润最大建立并求解模型。

Answer 1

model: sets: supply/1..4/:distance1; demand/1..5/:; goods/1..2/:tnum,weight,price; link1(supply,demand):distance2; link2(supply,goods):mproduce,cost,cementcost,steelcost; link3(goods,demand):booking; link4(supply,demand,goods):num; endsets data: tnum=2450 3600; price=10000 12000; distance1=20 35 60 40; weight=5 3; mproduce= 1000 1000 800 700 500 800 450 1200; cost= 6000 8600 6500 8500 6400 8550 5950 8700; cementcost= 4000 2000 4050 2050 4050 2060 4000 1990; steelcost= 1000 600 1050 510 1030 510 990 515; distance2= 15 12 19 25 9 12 18 15 18 17 17 10 14 11 15 16 9 18 13 20; booking= 450 520 600 500 380 900 600 1000 500 600; enddata max=@sum(goods:tnum*price)-@sum(link2(i,j):cost(i,j)*@sum(demand(k):num(i,k,j))) -0.2*@sum(supply(i):distance1(i)*@sum(goods(j):@sum(demand(k):num(i,k,j))*cementcost(i,j)/1000)) -0.3*@sum(supply(i):distance1(i)*@sum(goods(j):@sum(demand(k):num(i,k,j))*steelcost(i,j)/1000)) -@sum(link1(i,k):distance2(i,k)*@sum(goods(j):weight(j)*num(i,k,j))); @sum(supply(i):@sum(goods(j):@sum(demand(k):num(i,k,j))*cementcost(i,j)))<=23000000; @sum(supply(i):@sum(goods(j):@sum(demand(k):num(i,k,j))*steelcost(i,j)))<=9000000; @for(link2(i,j):@sum(demand(k):num(i,k,j))<=mproduce(i,j)); @for(link3(j,k):@sum(supply(i):num(i,k,j))=booking(j,k)); @for(link4:@gin(num)); end