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y=kx+2k+1x+2y-4=0解得x=(2-4k)/(2k+1)y=(6k+1)/(2k+1)是怎么解出来的,
题目详情
y = kx + 2k + 1
x + 2y - 4 = 0
解得x = (2 - 4k)/(2k + 1)
y = (6k + 1)/(2k + 1) 是怎么解出来的,
x + 2y - 4 = 0
解得x = (2 - 4k)/(2k + 1)
y = (6k + 1)/(2k + 1) 是怎么解出来的,
▼优质解答
答案和解析
(1)代入(2)得x+2(kx+2k+1)-4=0x+2kx+4k+2-4=0(2k+1)x=2-4k∴x=(2-4k)/(2k+1)把x=(2-4k)/(2k+1)代入(1)得y=k(2-4k)/(2k+1)+(2k+1)=[2k-4k²+4k²+4k+1)/(2k+1)=(6k+1)/(2k+1)
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