设实数a.b.c满足a≥b≥c,且√(1/a^2+1/b^2+1/c^2)=|1/a+1/b+1/c|,则直线y=(a/b)x=c/d必定经过象限是直线y=(a/b)x+c/b错了,不好意思

Question

设实数a.b.c满足a≥b≥c,且√(1/a^2+1/b^2+1/c^2)=|1/a+1/b+1/c|,则直线y=(a/b)x=c/d必定经过_________象限
是直线y=(a/b)x+c/b
错了,不好意思

Answer 1

∵√(1/a^2+1/b^2+1/c^2)=|1/a+1/b+1/c|,
∴两边平方,化简得a+b+c=0
a≥b≥c,∴a一定大于0,c一定小于0
y=(a/b)x+c/b
当b>0时,直线过一、三、四象限
当b