计算（1）log327+lg25+lg4+7log72+(−9.8)0（2）614−(π−1)0−(338)13+(164)−23．

Question

计算
（1）log3√(27)+lg25+lg4+7log72+(−9.8)0
（2）√(6(1)/(4))−(π−1)0−(3(3)/(8))(1)/(3)+((1)/(64))−(2)/(3)．

Answer 1

（1）原式=log₃3 (3)/(2)+lg（25×4）+2+1=(3)/(2)+lg100+2+1=(3)/(2)+2+2+1＝(13)/(2)．
（2）原式=√((25)/(4))−1−((27)/(8))(1)/(3)+64(2)/(3)=(5)/(2)−1−((3)/(2))3×(1)/(3)+43×(2)/(3)=(5)/(2)−1−(3)/(2)+16＝16．