早教吧作业答案频道 -->英语-->
适当形式填空youcanfindmany(attract)onboard1、youcanfindmany(attract)onboard2、thebabyisn't(wake).heisstillasleep.3、inever(see)thefilmbefore4、it'simpolittoask(person)questionthree(five)ofthestud
题目详情
适当形式填空 you can find many___( attract) on board
1、you can find many___( attract) on board
2、thebaby isn't___(wake).he is still asleep.
3、i___never___(see)the film before
4、it's impolit to ask___(person)question
three___(five)of the students are girls in our class
1、you can find many___( attract) on board
2、thebaby isn't___(wake).he is still asleep.
3、i___never___(see)the film before
4、it's impolit to ask___(person)question
three___(five)of the students are girls in our class
▼优质解答
答案和解析
1.attractions
2.awake
3.have...seen
4.personal
5.fifths
2.awake
3.have...seen
4.personal
5.fifths
看了适当形式填空youcanfin...的网友还看了以下：
椭圆方程式的题椭圆方程x^2/a^2+y^2/b^2=t怎么用y=f(u),x=f(u)表示如果椭 2020-05-16 …
变限积分求道问题对函数f(t+h)-f(t-h)在[-h,h]上的积分对h求导.F(h)=∫[-h 2020-05-23 …
求解一道卷积的题f(t)=t^2t≥0g(t)=u(t-1)t≥0求f*g不好意思忘了说了u(t- 2020-07-19 …
设函数f（x）在[0，+∞]内连续，f（1）=52，且对所有x，t∈（0，+∞），满足条件∫xt1 2020-07-26 …
阶跃函数积分f(t)=u(t)-u(t-1)怎么求f(t)的下限为负无穷上限为t的积分啊 2020-07-31 …
对于积分上限函数∫(a,t)f(y)dy,知道被积函数是f(t).那么对于∫(a,t)f(x+y) 2020-08-02 …
高数定积分证明题y(x)在[a,b]上连续,在(a,b)上可导,证明：y(x)=定积分(上限u（x 2020-08-03 …
二.已知函数f(x)对任意的u,v属于R都有f(u+v)=f(u)+f(v)-2,当x大于0时,f( 2020-11-07 …
2道积分题1.设函数f（x）在（0,+∞）内连续,且f（1）=5/2,且对所有的x,t∈R,满足条件 2020-11-15 …
求fourier变换f(t)=u(t)(e^-βt)sinω0t(β>0)f(t)=u(t)(e^- 2021-01-07 …