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一道英文数学题..if a＜b,then 3^2+4^2+5^2+12^2=a^2+b^2 (符号^是平方) is satisfied by only one pair of positive intergers (a,b).what is the value of a+b?
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一道英文数学题..
if a＜b,then 3^2+4^2+5^2+12^2=a^2+b^2 (符号^是平方) is satisfied by only one pair of positive intergers (a,b).what is the value of a+b?
if a＜b,then 3^2+4^2+5^2+12^2=a^2+b^2 (符号^是平方) is satisfied by only one pair of positive intergers (a,b).what is the value of a+b?
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答案和解析
3^2+4^2+5^2+12^2=194
a^2+b^2=194
那么a=5,b=13
3^2+4^2=25,可以是5的平方
5^2+12^2可以是13的平方
那么the value of a+b,a+b的结果就是13+5=18
a^2+b^2=194
那么a=5,b=13
3^2+4^2=25,可以是5的平方
5^2+12^2可以是13的平方
那么the value of a+b,a+b的结果就是13+5=18
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