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已知x²-4x+y²-10y+29=0,求x²y²+2x³y²+x四次方y²的值
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已知x²-4x+y²-10y+29=0,求x²y²+2x³y²+x四次方y²的值
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x²-4x+y²-10y+29=0
（x²-4x+4)+(y²-10y+25)=0
(x-2)²+(y-5)²=0
x-2=0,y-5=0
x=2,y=5
x²y²+2x³y²+x四次方y²
=x²y²(1+2x+x²)
=x²y²(x+1)²
=4×25×9
=900
（x²-4x+4)+(y²-10y+25)=0
(x-2)²+(y-5)²=0
x-2=0,y-5=0
x=2,y=5
x²y²+2x³y²+x四次方y²
=x²y²(1+2x+x²)
=x²y²(x+1)²
=4×25×9
=900
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