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.先化简,后计算.[2x(x²y-xy²)+xy(xy-x²)]/x²yx=2008,y=2004
题目详情
.先化简,后计算.
[2x(x²y-xy²)+xy(xy-x²)]/x²y
x=2008,y=2004
[2x(x²y-xy²)+xy(xy-x²)]/x²y
x=2008,y=2004
▼优质解答
答案和解析
[2x(x²y-xy²)+xy(xy-x²)]/x²y
=[2x^3y-2x^2y^2+x^2y^2-x^3y]/x²y
=x-y
=4
=[2x^3y-2x^2y^2+x^2y^2-x^3y]/x²y
=x-y
=4
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