已知0＜β＜π/4,π/4＜α＜3π/4,cos（π/4-α）=3/5,sin（3π/4+β）=5/13,求sin（α＋β

Question

已知0＜β＜π/4,π/4＜α＜3π/4,cos（π/4-α）=3/5,sin（3π/4+β）=5/13,求sin（α＋β

Answer 1

因为π/40,
因为
-π/2cos(π/4-α)=3/5,
所以sin（π/4-α)= -4/5；
因为
3π/4sin(3π/4+β)=5/13
所以cos(3π/4+β)= -12/13
sin(3π/4+β-(π/4 -α))=sin(α+β+π/2)= - cos(α+β)=(5/13)*(3/5)-(-12/13)*(-4/5)=-33/65
sin(α+β)=√(1-(33/65)∧2)=(√3116)/65