Thenumberofvariouseducationalprogramsisincreasing,importantroleshavebeenrealizedbymoreandmorepeople.()A.whoseB.whereC.whichD.that
The number of various educational programs is increasing,_______ important roles have been realized by more and more people.( )
A. whose
B. where
C. which
D. that
\u7b54\u6848\uff1aA\uff0e\u8fd9\u662f\u9694\u4f4d\u4fee\u9970\u7684 \u5b9a\u8bed\u4ece\u53e5
\u539f\u53e5=The number of various educational programs whose important roles have been recognized by more and more people is increasing \u7b54\u6848\u586bwhose\uff0c\u56e0\u4e3a\u5b9a\u8bed\u592a\u957f\uff0c\u6545\u8c13\u8bed\u63d0\u524d\u4ee5\u514d\u5934\u91cd\u811a\u8f7b\uff0ethe number \u662f\u4e3b\u8bed\u4e0d\u662f\u5148\u884c\u8bcd\uff0c\u8c13\u8bedis increasing \u8bf4\u7684\u662f\u6570\u5b57\u5728\u589e\u957f\uff0c\u4e0e\u5b9a\u8bed\u4ece\u53e5\u5185\u5bb9\u65e0\u5173\uff0e\u5b9a\u8bed\u4ece\u53e5\u7684\u5148\u884c\u8bcd\u662fvarious educational programs\uff0e\u6240\u4ee5\u9009\u62e9A\uff0ewhose important roles \u8868\u793a\u6559\u80b2\u8282\u76ee\u7684\u91cd\u8981\u4f5c\u7528\uff0e" "latex":"
\u7b54\u6848\uff1aA\uff0e\u8fd9\u662f\u9694\u4f4d\u4fee\u9970\u7684 \u5b9a\u8bed\u4ece\u53e5
\u539f\u53e5=The number of various educational programs whose important roles have been recognized by more and more people is increasing \u7b54\u6848\u586bwhose\uff0c\u56e0\u4e3a\u5b9a\u8bed\u592a\u957f\uff0c\u6545\u8c13\u8bed\u63d0\u524d\u4ee5\u514d\u5934\u91cd\u811a\u8f7b\uff0ethe number \u662f\u4e3b\u8bed\u4e0d\u662f\u5148\u884c\u8bcd\uff0c\u8c13\u8bedis increasing \u8bf4\u7684\u662f\u6570\u5b57\u5728\u589e\u957f\uff0c\u4e0e\u5b9a\u8bed\u4ece\u53e5\u5185\u5bb9\u65e0\u5173\uff0e\u5b9a\u8bed\u4ece\u53e5\u7684\u5148\u884c\u8bcd\u662fvarious educational programs\uff0e\u6240\u4ee5\u9009\u62e9A\uff0ewhose important roles \u8868\u793a\u6559\u80b2\u8282\u76ee\u7684\u91cd\u8981\u4f5c\u7528\uff0e"}
关于求反函数的问题求y=shx的反函数,先解出x=shy=(e^y-e^y)/2,然后再令u=e^ 2020-05-13 …
设X,Y是两个随机变量,则下列等式中正确的是A,E(X+Y)=E(X)+E(Y)B,D(X+Y)= 2020-05-15 …
协方差等于零能推出相互独立吗?∵cov(X,Y)=0又∵cov(X,Y)=E(XY)-E(X协方差 2020-06-10 …
main(){unionEXAMPLE{struct{intx,y;}in;inta,b;}e;e 2020-06-12 …
对数函数y=e^x-e^-x/e^x+e^-x转化为用含y的式子表示x的形式.谢咯,对数函数y=e 2020-07-15 …
对数函数y=e^x-e^-x/e^x+e^-x转化为用含y的式子表示x的形式.谢咯,对数函数y=e 2020-07-15 …
,Var(X+Y)=Var(X)+Var(Y)设随机变量X,Y的数学期望和方差都存在,则下式中一定 2020-07-19 …
d/dx(e^y+xy-e)=e^ydy/dx+y+xdy/dx,这是教科书上的等式,对等式左边x 2020-07-19 …
已知函数y=(e^x-a)^2+(e^(-x)-a)^2(a属于R,a不等于0),求y的最小值Y= 2020-07-21 …
高数反函数求导问题求函数y=(e^x-e^(-x))/(e^x+e^(-x))的反函数的导数x'(y 2021-01-23 …